1+(3/x+1)=(3/x^2+3x+2)

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Solution for 1+(3/x+1)=(3/x^2+3x+2) equation: 



1+(3/x+1)=(3/x^2+3x+2)

We move all terms to the left:

1+(3/x+1)-((3/x^2+3x+2))=0



Domain of the equation: x+1)!=0

x∈R





Domain of the equation: x^2+3x+2))!=0

x∈R



We get rid of parentheses

3/x-((3/x^2+3x+2))+1+1=0

We calculate fractions

We do not support expression: x^3

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